Optimal. Leaf size=106 \[ \frac {2 a e F_1\left (-\frac {1}{2};\frac {1-m}{2},\frac {1}{2} (-2-m);\frac {1}{2};\cos (c+d x),-\cos (c+d x)\right ) (1-\cos (c+d x))^{\frac {1-m}{2}} (1+\cos (c+d x))^{-m/2} \sqrt {a+a \sec (c+d x)} (e \sin (c+d x))^{-1+m}}{d} \]
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Rubi [A]
time = 0.24, antiderivative size = 106, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 4, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.160, Rules used = {3961, 2965,
140, 138} \begin {gather*} \frac {2 a e \sqrt {a \sec (c+d x)+a} (1-\cos (c+d x))^{\frac {1-m}{2}} (\cos (c+d x)+1)^{-m/2} F_1\left (-\frac {1}{2};\frac {1-m}{2},\frac {1}{2} (-m-2);\frac {1}{2};\cos (c+d x),-\cos (c+d x)\right ) (e \sin (c+d x))^{m-1}}{d} \end {gather*}
Antiderivative was successfully verified.
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Rule 138
Rule 140
Rule 2965
Rule 3961
Rubi steps
\begin {align*} \int (a+a \sec (c+d x))^{3/2} (e \sin (c+d x))^m \, dx &=\frac {\left (\sqrt {-\cos (c+d x)} \sqrt {a+a \sec (c+d x)}\right ) \int \frac {(-a-a \cos (c+d x))^{3/2} (e \sin (c+d x))^m}{(-\cos (c+d x))^{3/2}} \, dx}{\sqrt {-a-a \cos (c+d x)}}\\ &=-\frac {\left (e \sqrt {-\cos (c+d x)} (-a-a \cos (c+d x))^{-\frac {1}{2}+\frac {1-m}{2}} (-a+a \cos (c+d x))^{\frac {1-m}{2}} \sqrt {a+a \sec (c+d x)} (e \sin (c+d x))^{-1+m}\right ) \text {Subst}\left (\int \frac {(-a-a x)^{\frac {3}{2}+\frac {1}{2} (-1+m)} (-a+a x)^{\frac {1}{2} (-1+m)}}{(-x)^{3/2}} \, dx,x,\cos (c+d x)\right )}{d}\\ &=\frac {\left (a e \sqrt {-\cos (c+d x)} (1+\cos (c+d x))^{-m/2} (-a-a \cos (c+d x))^{-\frac {1}{2}+\frac {1-m}{2}+\frac {m}{2}} (-a+a \cos (c+d x))^{\frac {1-m}{2}} \sqrt {a+a \sec (c+d x)} (e \sin (c+d x))^{-1+m}\right ) \text {Subst}\left (\int \frac {(1+x)^{\frac {3}{2}+\frac {1}{2} (-1+m)} (-a+a x)^{\frac {1}{2} (-1+m)}}{(-x)^{3/2}} \, dx,x,\cos (c+d x)\right )}{d}\\ &=\frac {\left (a e (1-\cos (c+d x))^{\frac {1}{2}-\frac {m}{2}} \sqrt {-\cos (c+d x)} (1+\cos (c+d x))^{-m/2} (-a-a \cos (c+d x))^{-\frac {1}{2}+\frac {1-m}{2}+\frac {m}{2}} (-a+a \cos (c+d x))^{-\frac {1}{2}+\frac {1-m}{2}+\frac {m}{2}} \sqrt {a+a \sec (c+d x)} (e \sin (c+d x))^{-1+m}\right ) \text {Subst}\left (\int \frac {(1-x)^{\frac {1}{2} (-1+m)} (1+x)^{\frac {3}{2}+\frac {1}{2} (-1+m)}}{(-x)^{3/2}} \, dx,x,\cos (c+d x)\right )}{d}\\ &=\frac {2 a e F_1\left (-\frac {1}{2};\frac {1-m}{2},\frac {1}{2} (-2-m);\frac {1}{2};\cos (c+d x),-\cos (c+d x)\right ) (1-\cos (c+d x))^{\frac {1-m}{2}} (1+\cos (c+d x))^{-m/2} \sqrt {a+a \sec (c+d x)} (e \sin (c+d x))^{-1+m}}{d}\\ \end {align*}
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Mathematica [B] Leaf count is larger than twice the leaf count of optimal. \(1243\) vs. \(2(106)=212\).
time = 8.43, size = 1243, normalized size = 11.73 \begin {gather*} \frac {4 (3+m) \left (F_1\left (\frac {1+m}{2};-\frac {1}{2},1+m;\frac {3+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )+F_1\left (\frac {1+m}{2};\frac {1}{2},m;\frac {3+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )+2 F_1\left (\frac {1+m}{2};\frac {3}{2},m;\frac {3+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )\right ) \cos ^3\left (\frac {1}{2} (c+d x)\right ) (a (1+\sec (c+d x)))^{3/2} \sin \left (\frac {1}{2} (c+d x)\right ) (e \sin (c+d x))^m}{d (1+m) \left (6 F_1\left (\frac {1+m}{2};\frac {3}{2},m;\frac {3+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )+2 m F_1\left (\frac {1+m}{2};\frac {3}{2},m;\frac {3+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )-2 F_1\left (\frac {3+m}{2};-\frac {1}{2},2+m;\frac {5+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )-2 m F_1\left (\frac {3+m}{2};-\frac {1}{2},2+m;\frac {5+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )-F_1\left (\frac {3+m}{2};\frac {1}{2},1+m;\frac {5+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )-2 m F_1\left (\frac {3+m}{2};\frac {1}{2},1+m;\frac {5+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )+F_1\left (\frac {3+m}{2};\frac {3}{2},m;\frac {5+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )-4 m F_1\left (\frac {3+m}{2};\frac {3}{2},1+m;\frac {5+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )+6 F_1\left (\frac {3+m}{2};\frac {5}{2},m;\frac {5+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right )+6 F_1\left (\frac {1+m}{2};\frac {3}{2},m;\frac {3+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right ) \cos (c+d x)+2 m F_1\left (\frac {1+m}{2};\frac {3}{2},m;\frac {3+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right ) \cos (c+d x)+2 F_1\left (\frac {3+m}{2};-\frac {1}{2},2+m;\frac {5+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right ) \cos (c+d x)+2 m F_1\left (\frac {3+m}{2};-\frac {1}{2},2+m;\frac {5+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right ) \cos (c+d x)+F_1\left (\frac {3+m}{2};\frac {1}{2},1+m;\frac {5+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right ) \cos (c+d x)+2 m F_1\left (\frac {3+m}{2};\frac {1}{2},1+m;\frac {5+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right ) \cos (c+d x)-F_1\left (\frac {3+m}{2};\frac {3}{2},m;\frac {5+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right ) \cos (c+d x)+4 m F_1\left (\frac {3+m}{2};\frac {3}{2},1+m;\frac {5+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right ) \cos (c+d x)-6 F_1\left (\frac {3+m}{2};\frac {5}{2},m;\frac {5+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right ) \cos (c+d x)+(3+m) F_1\left (\frac {1+m}{2};-\frac {1}{2},1+m;\frac {3+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right ) (1+\cos (c+d x))+(3+m) F_1\left (\frac {1+m}{2};\frac {1}{2},m;\frac {3+m}{2};\tan ^2\left (\frac {1}{2} (c+d x)\right ),-\tan ^2\left (\frac {1}{2} (c+d x)\right )\right ) (1+\cos (c+d x))\right )} \end {gather*}
Warning: Unable to verify antiderivative.
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Maple [F]
time = 0.11, size = 0, normalized size = 0.00 \[\int \left (a +a \sec \left (d x +c \right )\right )^{\frac {3}{2}} \left (e \sin \left (d x +c \right )\right )^{m}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: SystemError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int {\left (e\,\sin \left (c+d\,x\right )\right )}^m\,{\left (a+\frac {a}{\cos \left (c+d\,x\right )}\right )}^{3/2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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